Effectuer un changement de variable pour retrouver une équation du second degré Exercice

S=\left\{ \varnothing \right\}

S=\left\{ -2;1 \right\}

S=\left\{ 1;-\sqrt[3]{6} \right\}

S=\left\{ -2;-1;1 ;2\right\}

S=\left\{ \varnothing \right\}

S=\left\{ \dfrac{1}{2};1 \right\}

S=\left\{ -1;-\dfrac{\sqrt{2}}{2};\dfrac{\sqrt{2}}{2};1 \right\}

S=\left\{ -1;-\dfrac{1}{4};\dfrac{1}{4};1 \right\}

S=\left\{ \varnothing \right\}

S=\left\{ -\sqrt{\dfrac{5}{6}};\sqrt{\dfrac{5}{6}} \right\}

S=\left\{ -\sqrt{2};-\dfrac{\sqrt{5}}{2};\dfrac{\sqrt{5}}{2};\sqrt{2} \right\}

S=\left\{ -\dfrac{1}{\sqrt{2}};-\dfrac{\sqrt{3}}{2};\dfrac{\sqrt{3}}{2};\dfrac{1}{\sqrt{2}} \right\}

S=\left\{ \varnothing \right\}

S=\left\{ \dfrac{\sqrt{3}}{2};-\dfrac{\sqrt{3}}{2} \right\}

S=\left\{ -\sqrt{5};-\dfrac{\sqrt{3}}{2};\dfrac{\sqrt{2}}{2};\sqrt{5} \right\}

S=\left\{ -\sqrt{5};-2;2;\sqrt{5} \right\}

S=\left\{ \varnothing \right\}

S=\left\{ \sqrt{3};-\sqrt{3} \right\}

S=\left\{\sqrt{ \dfrac{5}{2}};-\sqrt{ \dfrac{5}{2}};\sqrt{3};-\sqrt{3} \right\}

S=\left\{\sqrt{\dfrac{5}{2}};-\sqrt{\dfrac{5}{2}} \right\}

S=\left\{ -\dfrac{1}{3};-\dfrac{1}{2};\dfrac{1}{2};\dfrac{1}{3}\right\}

S=\left\{-3;-2;2;3 \right\}

S=\left\{ -\dfrac{1}{4};-\dfrac{1}{9};\dfrac{1}{9};\dfrac{1}{4}\right\}

S= \varnothing

S=\left\{ -\dfrac{\sqrt{6}}{2};\dfrac{\sqrt{6}}{2} \right\}

S=\left\{ -\dfrac{\sqrt{3}}{2};\dfrac{\sqrt{3}}{2} \right\}

S=\left\{ \sqrt{\dfrac{3}{2}} \right\}

S= \varnothing