\dfrac{x^2+4x+4}{x^2-9}\lt0

S=\left] -3;-2 \right[\cup\left] -2;3 \right[

S=\left] -3;-2 \right]\cup\left[ -2;3 \right[

S=\left[ -3;-2 \right[\cup\left] -2;3 \right]

S=\left[ -3;-2 \right]\cup\left[ -2;3 \right]

\dfrac{-x^2+5x-10}{4x^2-12x+9}\gt0

S=\varnothing

S = \mathbb{R}

S = \left]0; +\infty\right[

S = \left[0; +\infty\right[

\dfrac{-2x^2+x-5}{-3x+7}\lt0

S=\left] -\infty;\dfrac{7}{3} \right[

S=\left] \dfrac{7}{3}; +\infty \right[

S=\left] -\infty;\dfrac{-7}{3} \right[

S=\left] \dfrac{-7}{3}; +\infty \right[

\dfrac{-3x^2+x+4}{-7x+2}\leqslant0

S=\left] -\infty;-1 \right]\cup\left] \dfrac{2}{7};\dfrac{4}{3} \right]

S=\left] -\infty;-1 \right[\cup\left] \dfrac{2}{7};\dfrac{4}{3} \right[

S=\left] -\infty;-1 \right]\cup\left[ \dfrac{2}{7};\dfrac{4}{3} \right]

S=\left] -\infty;-1 \right[\cup\left[ \dfrac{2}{7};\dfrac{4}{3} \right[

\dfrac{5x+2}{x^2-5x+6}\lt0

S=\left] -\infty;-\dfrac{2}{5} \right[\cup\left]2;3 \right[

S=\left] -\infty;-\dfrac{2}{5} \right]\cup\left[2;3 \right]

S=\left] -\infty;-\dfrac{2}{5} \right]\cup\left]2;3 \right[

S=\left] -\infty;-\dfrac{2}{5} \right[\cup\left[2;3 \right]