Déterminer la forme canonique d'un trinôme Exercice

P\left(x\right)=3\left(x+\dfrac{1}{3}\right)^{2}+3

P\left(x\right)=3\left(x^{2}+\dfrac{1}{3}x+1\right)

P\left(x\right)=3\left(x+\dfrac{1}{6}\right)^{2}+\dfrac{35}{12}

P\left(x\right)=3\left(x+\dfrac{1}{3}\right)^{2}+\dfrac{8}{3}

P\left(x\right)=\left(x-5\right)^{2}-6

P\left(x\right)=\left(x-10\right)^{2}+19

P\left(x\right)=x\left(x-10\right)+19

P\left(x\right)=\left(x-5\right)^{2}+44

P\left(x\right)=-\left(x+3\right)^{2}-3

P\left(x\right)=\left(-x+3\right)^{2}-6

P\left(x\right)=-\left(x-3\right)^{2}-3

P\left(x\right)=-\left(x-3\right)^{2}+6

P\left(x\right)=-3\left(x-\dfrac{5}{2}\right)^{2}+\dfrac{87}{4}

P\left(x\right)=-3\left(x-\dfrac{5}{6}\right)^{2}+\dfrac{1}{12}

P\left(x\right)=-3\left(x-\dfrac{5}{6}\right)^{2}+\dfrac{49}{12}

P\left(x\right)=-3\left(x-\dfrac{5}{6}\right)^{2}-2

P\left(x\right)=-2\left(x-2\right)^{2}+2

P\left(x\right)=2\left(x+2\right)^{2}-2

P\left(x\right)=2\left(x+2\right)^{2}-14

P\left(x\right)=-2\left(x+2\right)^{2}+2