Résoudre une inéquation trigonométrique du type sin(x)>a Exercice

S_1 = \left[0 ;\dfrac{7\pi}{6} \right] \cup \left[\dfrac{11\pi}{6} ; 2\pi\right]

S_1 = \left[\dfrac{\pi}{6} ;\dfrac{5\pi}{6} \right]

S_1 = \left[0 ;\dfrac{\pi}{6} \right] \cup \left[\dfrac{5\pi}{6} ; 2\pi\right]

S_1 = \left[-\pi ;-\dfrac{5\pi}{6} \right] \cup \left[-\dfrac{\pi}{6} ; \pi\right]

S_2 = \left[-\pi ;-\dfrac{5\pi}{6} \right] \cup \left[-\dfrac{\pi}{6} ; \pi\right]

S_2 = \left[-\dfrac{5\pi}{6};-\dfrac{\pi}{6} \right]

S_2 = \left[-\pi ; \dfrac{\pi}{6} \right] \cup \left[\dfrac{5\pi}{6} ; \pi \right]

S_2 = \left[-\pi ; \dfrac{\pi}{3} \right] \cup \left[\dfrac{2\pi}{3} ; \pi \right]

S_3 =\bigcup_{k\in\mathbb{Z}} \left[-\pi+k2\pi ;\dfrac{\pi}{6}+k2\pi \right[ \cup \left[\dfrac{5\pi}{6} +k2\pi; \pi+k2\pi \right]

S_3 =\bigcup_{k\in\mathbb{Z}} \left[ \dfrac{\pi}{6}+k2\pi ; \dfrac{5\pi}{6} +k2\pi\right]

S_3 =\bigcup_{k\in\mathbb{Z}} \left[ 0+k2\pi ; \dfrac{\pi}{6} +k2\pi\right] \cup \left[ \dfrac{5\pi}{6} +k2\pi; 2\pi +k2\pi\right[

S_3 = \bigcup_{k\in\mathbb{Z}}\left[ 0+k2\pi ; \dfrac{7\pi}{6} +k2\pi\right] \cup \left[ \dfrac{11\pi}{6} +k2\pi; 2\pi +k2\pi\right]