Déterminer la demi-équation acidobasique d'un couple acide-base - Tle - Exercice Physique-Chimie

On considère le couple acide/base suivant :
\ce{HCOOH}/\ce{HCOO-}

Quelle est la demi-équation de ce couple ?

\ce{HCOOH} = \ce{HCOO-}+\ce{H+}

\ce{HCOOH} + \ce{H+} = \ce{HCOO-}

\ce{HCOOH} +\ce{OH-} = \ce{HCOO-}

\ce{HCOO-} = \ce{HCOOH}+\ce{H+}

On considère le couple acide/base suivant :
\ce{H3O+}/\ce{H2O}

Quelle est la demi-équation de ce couple ?

\ce{H3O+} = \ce{H2O}+\ce{H+}

\ce{H3O+} +\ce{H+} = \ce{H2O}

\ce{H3O+} +\ce{OH-} = \ce{H2O}

\ce{H3O+} = \ce{H2O} +\ce{OH-}

On considère le couple acide/base suivant :
\ce{CH3COOH}/\ce{CH3COO-}

Quelle est la demi-équation de ce couple ?

\ce{CH3COOH} = \ce{CH3COO-}+\ce{H+}

\ce{CH3COOH} +\ce{H+} = \ce{CH3COO-}

\ce{CH3COOH} +\ce{OH-} = \ce{CH3COO-}

\ce{CH3COOH} = \ce{CH3COO-} +\ce{OH-}

On considère le couple acide/base suivant :
\ce{NH4+}/\ce{NH3}

Quelle est la demi-équation de ce couple ?

\ce{NH4+} = \ce{NH3}+\ce{H+}

\ce{NH4+} +\ce{H+} = \ce{NH3}

\ce{NH4+} +\ce{OH-} = \ce{NH3}

\ce{NH4+} = \ce{NH3} +\ce{OH-}

On considère le couple acide/base suivant :
\ce{HNO3}/\ce{NO3-}

Quelle est la demi-équation de ce couple ?

\ce{HNO3} = \ce{NO3-}+\ce{H+}

\ce{HNO3} +\ce{H+} = \ce{NO3-}

\ce{HNO3} +\ce{OH-} = \ce{NO3-}

\ce{HNO3} = \ce{NO3-} +\ce{OH-}