Résoudre une équation du second degré à coefficients réels dans C - TS - Exercice Mathématiques

z^2-z+1=0

S=\left\{ \dfrac{1}{2}+\dfrac{\sqrt{3}}{2}i; \dfrac{1}{2}-\dfrac{\sqrt{3}}{2}i\right\}

S=\left\{ -\dfrac{1}{2}+\dfrac{\sqrt{3}}{2}i; \dfrac{1}{2}-\dfrac{\sqrt{3}}{2}i\right\}

S=\left\{- \dfrac{1}{2}+\dfrac{\sqrt{3}}{2}i;- \dfrac{1}{2}-\dfrac{\sqrt{3}}{2}i\right\}

S=\left\{ \dfrac{1}{2}-\dfrac{\sqrt{3}}{2}; \dfrac{1}{2}+\dfrac{\sqrt{3}}{2}\right\}

-z^2+2z-2=0

S=\left\{ 1-i; 1+i\right\}

S=\left\{ 1+i; 1+i\right\}

S=\left\{ 1-i; 1-i\right\}

S=\left\{ -1-i; -1+i\right\}

5z^2-3z+\dfrac{5}{4}=0

S=\left\{ \dfrac{3}{10}-\dfrac{2}{5}i; \dfrac{3}{10}+\dfrac{2}{5}i\right\}

S=\left\{ \dfrac{3}{10}+\dfrac{2}{5}i; \dfrac{3}{10}+\dfrac{2}{5}i\right\}

S=\left\{ \dfrac{3}{10}-\dfrac{2}{5}i; \dfrac{3}{10}-\dfrac{2}{5}i\right\}

S=\left\{ \dfrac{3}{10}+\dfrac{2}{5}i; \dfrac{3}{10}-\dfrac{2}{5}i\right\}

3z^2-4z+2=0

S=\left\{ \dfrac{2}{3}-\dfrac{\sqrt2}{3}i; \dfrac{2}{3}+\dfrac{\sqrt2}{3}i\right\}

S=\left\{ \dfrac{2}{3}+\dfrac{\sqrt2}{3}i; \dfrac{2}{3}+\dfrac{\sqrt2}{3}i\right\}

S=\left\{ \dfrac{2}{3}-\dfrac{\sqrt2}{3}i; \dfrac{2}{3}-\dfrac{\sqrt2}{3}i\right\}

S=\left\{ \dfrac{2}{3}+\dfrac{\sqrt2}{3}i; \dfrac{2}{3}-\dfrac{\sqrt2}{3}i\right\}

-2z^2+2z-5=0

S=\left\{ \dfrac{1}{2}-\dfrac{3}{2}i;\dfrac{1}{2}+\dfrac{3}{2}i \right\}

S=\left\{ \dfrac{1}{2}+\dfrac{3}{2}i;\dfrac{1}{2}+\dfrac{3}{2}i \right\}

S=\left\{ \dfrac{1}{2}-\dfrac{3}{2}i;\dfrac{1}{2}-\dfrac{3}{2}i \right\}

S=\left\{ \dfrac{1}{2}+\dfrac{3}{2}i;\dfrac{1}{2}-\dfrac{3}{2}i \right\}

17z^2+5z+\dfrac{1}{2}=0

S=\left\{ -\dfrac{5}{34}-\dfrac{3}{34}i;-\dfrac{5}{34}+\dfrac{3}{34}i\right\}

S=\left\{ \dfrac{5}{34}-\dfrac{3}{34}i;-\dfrac{5}{34}+\dfrac{3}{34}i\right\}

S=\left\{ -\dfrac{5}{34}+\dfrac{3}{34}i;-\dfrac{5}{34}+\dfrac{3}{34}i\right\}

S=\left\{ -\dfrac{5}{34}-\dfrac{3}{34}i;-\dfrac{5}{34}-\dfrac{3}{34}i\right\}

-6z^2+7z-\dfrac{5}{2}=0

S=\left\{ \dfrac{7}{12}-\dfrac{\sqrt{11}}{12}i ;\dfrac{7}{12}+\dfrac{\sqrt{11}}{12}i \right\}

S=\left\{ \dfrac{7}{12}+\dfrac{\sqrt{11}}{12}i ;\dfrac{7}{12}-\dfrac{\sqrt{11}}{12}i \right\}

S=\left\{ \dfrac{7}{12}-\dfrac{\sqrt{11}}{12}i ;-\dfrac{7}{12}+\dfrac{\sqrt{11}}{12}i \right\}

S=\left\{ -\dfrac{7}{12}-\dfrac{\sqrt{11}}{12}i ;\dfrac{7}{12}+\dfrac{\sqrt{11}}{12}i \right\}