Calculer une intégrale Exercice

\int_{0}^{1} 2x^3-11x \ \mathrm dx=-5

\int_{0}^{1} 2x^3-11x \ \mathrm dx=2

\int_{0}^{1} 2x^3-11x \ \mathrm dx=6

\int_{0}^{1} 2x^3-11x \ \mathrm dx=-9

I=\int_{0}^{1}\dfrac{\ln\left(x+3\right)}{x+3} \ \mathrm dx=\dfrac{\left(\ln\left(4\right)\right)^2-\left(\ln\left(3\right)\right)^2}{2}

I=\int_{0}^{1}\dfrac{\ln\left(x+3\right)}{x+3} \ \mathrm dx=\dfrac{3\ln\left(4\right)-4\ln\left(3\right)}{12}

I=\int_{0}^{1}\dfrac{\ln\left(x+3\right)}{x+3} \ \mathrm dx=\ln\left(\ln\left(4\right)\right)-\ln\left(\ln\left(3\right)\right)

I=\int_{0}^{1}\dfrac{\ln\left(x+3\right)}{x+3} \ \mathrm dx=\dfrac{1-\ln\left(4\right)}{16}-\dfrac{1-\ln\left(3\right)}{9}

I=\int_{0}^{2}\left(2x-5\right)^6 \ \mathrm dx=\dfrac{39\ 062}{7}

I=\int_{0}^{2}\left(2x-5\right)^6 \ \mathrm dx=37\ 488

I=\int_{0}^{2}\left(2x-5\right)^6 \ \mathrm dx=15\ 626

I=\int_{0}^{2}\left(2x-5\right)^6 \ \mathrm dx=\dfrac{37\ 969}{7}

I=\int_{-1}^{3}\dfrac{1}{x+5} \ \mathrm dx=\ln\left(2\right)

I=\int_{-1}^{3}\dfrac{1}{x+5} \ \mathrm dx=\ln\left(4\right)

I=\int_{-1}^{3}\dfrac{1}{x+5} \ \mathrm dx=-\dfrac{1}{8}

I=\int_{-1}^{3}\dfrac{1}{x+5} \ \mathrm dx=\dfrac{3}{64}

I=\int_{0}^{2}e^{-x-3}\ \mathrm dx=e^{-3}-e^{-5}

I=\int_{0}^{2}e^{-x-3}\ \mathrm dx=e^{-5}-e^{-3}

I=\int_{0}^{2}e^{-x-3}\ \mathrm dx=e^{-2}-1

I=\int_{0}^{2}e^{-x-3}\ \mathrm dx=1-e^{-2}

I=\int_{-1}^{0}xe^{x^2}\ \mathrm dx=\dfrac{1-e}{2}

I=\int_{-1}^{0}xe^{x^2}\ \mathrm dx=1-3e

I=\int_{-1}^{0}xe^{x^2}\ \mathrm dx=e

I=\int_{-1}^{0}xe^{x^2}\ \mathrm dx=-\dfrac{e}{2}

I=\int_{2}^{3}\dfrac{2x+1}{x^2+x}\ \mathrm dx=\ln\left(2\right)

I=\int_{2}^{3}\dfrac{2x+1}{x^2+x}\ \mathrm dx=-\dfrac{1}{4}

I=\int_{2}^{3}\dfrac{2x+1}{x^2+x}\ \mathrm dx=-\ln\left(4\right)

I=\int_{2}^{3}\dfrac{2x+1}{x^2+x}\ \mathrm dx=\dfrac{27}{144}