Factoriser un polynôme - 2nde - Problème Mathématiques

f\left(x\right)=\left(4x-8\right)\left(x^{2}-1\right)

f\left(x\right)=4\left(x-2\right)\left(x-1\right)\left(x+1\right)

f\left(x\right)=4\left(x-2\right)\left(x^{2}-1\right)

f\left(x\right)=\left(4x-8\right)\left(x-1\right)\left(x+1\right)

f\left(x\right)=\left(8x-8\right)\left(x-1\right)+\left(2x-2\right)

f\left(x\right)=2\left(x-1\right)\left(4x-3\right)

f\left(x\right)=4\left(2x-2\right)\left(x-1\right)

f\left(x\right)=4\left(2x-2\right)\left(x-1\right)+1

f\left(x\right)=4\left(2x-2\right)\left(x-1\right)+\left(2x-2\right)

f\left(x\right)=\left(4x^{2}-9\right)\left(2x-1\right)

f\left(x\right)=\left(2x-3\right)\left(2x+3\right)\left(2x-1\right)

f\left(x\right)=\left(4x^{2}-9\right)\left(2x-1\right)

f\left(x\right)=\left(4x-3\right)\left(4x+3\right)\left(2x-1\right)

f\left(x\right)=\left(2x-9\right)\left(2x+9\right)\left(2x-1\right)

f\left(x\right)=\left(5x^{2}-5x\right)\left(-25x-5\right)

f\left(x\right)=-25x\left(x-1\right)\left(5x+1\right)

f\left(x\right)=25x\left(x-1\right)\left(5x+1\right)

f\left(x\right)=-25x\left(x-1\right)\left(5x-1\right)

f\left(x\right)=-25x\left(x+1\right)\left(5x+1\right)