Calculer le cosinus ou le sinus d'un angle associé - 2nde - Exercice Mathématiques

Quelle est la valeur de cos\left(-\dfrac{\pi}{6}\right) et de sin\left(-\dfrac{\pi}{6}\right) ?

\cos\left(-\dfrac{\pi}{6}\right) = \dfrac{\sqrt{3}}{2} et \sin\left(-\dfrac{\pi}{6}\right) = - \dfrac{1}{2}

\cos\left(-\dfrac{\pi}{6}\right) = \dfrac{{1}}{2} et \sin\left(-\dfrac{\pi}{6}\right) = - \dfrac{\sqrt{3}}{2}

\cos\left(-\dfrac{\pi}{6}\right) = \dfrac{\sqrt{3}}{2} et \sin\left(-\dfrac{\pi}{6}\right) = \dfrac{1}{2}

\cos\left(-\dfrac{\pi}{6}\right) = \dfrac{\sqrt{2}}{2} et \sin\left(-\dfrac{\pi}{6}\right) = -\dfrac{\sqrt{2}}{2}

Quelle est la valeur de cos\left(-\dfrac{\pi}{4}\right) et de sin\left(-\dfrac{\pi}{4}\right) ?

\cos\left(-\dfrac{\pi}{4}\right) = \dfrac{\sqrt{2}}{2} et \sin\left(-\dfrac{\pi}{4}\right) = - \dfrac{\sqrt{2}}{2}

\cos\left(-\dfrac{\pi}{4}\right) =- \dfrac{\sqrt{2}}{2} et \sin\left(-\dfrac{\pi}{4}\right) = \dfrac{\sqrt{2}}{2}

\cos\left(-\dfrac{\pi}{4}\right) = \dfrac{\sqrt{3}}{2} et \sin\left(-\dfrac{\pi}{4}\right) = - \dfrac{{1}}{2}

\cos\left(-\dfrac{\pi}{4}\right) = -1 et \sin\left(-\dfrac{\pi}{4}\right) = 0

Quelle est la valeur de cos\left(\dfrac{4\pi}{3}\right) et de sin\left(\dfrac{4\pi}{3}\right) ?

\cos\left(\dfrac{4\pi}{3}\right) = -\dfrac{1}{2} et \sin\left(\dfrac{4\pi}{3}\right) = - \dfrac{\sqrt{3}}{2}

\cos\left(\dfrac{4\pi}{3}\right) =\dfrac{1}{2} et \sin\left(\dfrac{4\pi}{3}\right) = - \dfrac{\sqrt{3}}{2}

\cos\left(\dfrac{4\pi}{3}\right) = -\dfrac{1}{2} et \sin\left(\dfrac{4\pi}{3}\right) = \dfrac{\sqrt{3}}{2}

\cos\left(\dfrac{4\pi}{3}\right) = \dfrac{\sqrt{2}}{2} et \sin\left(\dfrac{4\pi}{3}\right) = - \dfrac{\sqrt{2}}{2}

Quelle est la valeur de cos\left(\dfrac{5\pi}{6}\right) et de sin\left(\dfrac{5\pi}{6}\right) ?

\cos\left(\dfrac{5\pi}{6}\right) = -\dfrac{\sqrt{3}}{2} et \sin\left(\dfrac{5\pi}{6}\right) = \dfrac{1}{2}

\cos\left(\dfrac{5\pi}{6}\right) =\dfrac{\sqrt{3}}{2} et \sin\left(\dfrac{5\pi}{6}\right) = \dfrac{1}{2}

\cos\left(\dfrac{5\pi}{6}\right) = -\dfrac{\sqrt{3}}{2} et \sin\left(\dfrac{5\pi}{6}\right) =- \dfrac{1}{2}

\cos\left(\dfrac{5\pi}{6}\right) = -\dfrac{\sqrt{2}}{2} et \sin\left(\dfrac{5\pi}{6}\right) =\dfrac{\sqrt{2}}{2}

Quelle est la valeur de cos\left(-\dfrac{\pi}{2}\right) et de sin\left(-\dfrac{\pi}{2}\right) ?

\cos\left(-\dfrac{\pi}{2}\right) = 0 et \sin\left(-\dfrac{\pi}{2}\right) = - 1

\cos\left(-\dfrac{\pi}{2}\right) = 0 et \sin\left(-\dfrac{\pi}{2}\right) = 1

\cos\left(-\dfrac{\pi}{2}\right) = -1 et \sin\left(-\dfrac{\pi}{2}\right) = 0

\cos\left(-\dfrac{\pi}{2}\right) = 1 et \sin\left(-\dfrac{\pi}{2}\right) = 0

Quelle est la valeur de cos\left(\dfrac{5\pi}{4}\right) et de sin\left(\dfrac{5\pi}{4}\right) ?

\cos\left(\dfrac{5\pi}{4}\right) = -\dfrac{\sqrt{2}}{2} et \sin\left(\dfrac{5\pi}{4}\right) = -\dfrac{\sqrt{2}}{2}

\cos\left(\dfrac{5\pi}{4}\right) = \dfrac{\sqrt{2}}{2} et \sin\left(\dfrac{5\pi}{4}\right) = \dfrac{\sqrt{2}}{2}

\cos\left(\dfrac{5\pi}{4}\right) = \dfrac{\sqrt{2}}{2} et \sin\left(\dfrac{5\pi}{4}\right) = -\dfrac{\sqrt{2}}{2}

\cos\left(\dfrac{5\pi}{4}\right) = -\dfrac{\sqrt{2}}{2} et \sin\left(\dfrac{5\pi}{4}\right) =\dfrac{\sqrt{2}}{2}

Quelle est la valeur de cos\left(\dfrac{3\pi}{4}\right) et de sin\left(\dfrac{3\pi}{4}\right) ?

\cos\left(\dfrac{3\pi}{4}\right) = -\dfrac{\sqrt{2}}{2} et \sin\left(\dfrac{3\pi}{4}\right) = \dfrac{\sqrt{2}}{2}

\cos\left(\dfrac{3\pi}{4}\right) =\dfrac{\sqrt{2}}{2} et \sin\left(\dfrac{3\pi}{4}\right) = \dfrac{\sqrt{2}}{2}

\cos\left(\dfrac{3\pi}{4}\right) = \dfrac{\sqrt{2}}{2} et \sin\left(\dfrac{3\pi}{4}\right) = -\dfrac{\sqrt{2}}{2}

\cos\left(\dfrac{3\pi}{4}\right) = -\dfrac{\sqrt{2}}{2} et \sin\left(\dfrac{3\pi}{4}\right) =- \dfrac{\sqrt{2}}{2}