Calculer des probabilités dans le cadre d'une loi binomiale Exercice

p\left( X=2 \right)=15\left( \dfrac{1}{4}\right)^2\left(\dfrac{3}{4}\right)^4

p\left( X=2 \right)=\left( \dfrac{1}{4}\right)^2\left(\dfrac{3}{4}\right)^4

p\left( X=2 \right)=15\left( \dfrac{3}{4}\right)^2\left(\dfrac{1}{4}\right)^4

p\left( X=2 \right)=\left( \dfrac{1}{4}\right)^2\left(\dfrac{3}{4}\right)^2

p\left(X \geqslant5\right) = \left(\dfrac{1}{4}\right)^5 \times\dfrac{19}{4}

p\left(X \geqslant5\right) = \left(\dfrac{3}{4}\right)^5 \times\dfrac{19}{4}

p\left(X \geqslant5\right) = \left(\dfrac{1}{4}\right)^6 \times\dfrac{19}{3}

p\left(X \geqslant5\right) = \left(\dfrac{1}{4}\right)^5 \times\dfrac{19}{3}

p\left( X\geqslant1 \right)=1-\left( \dfrac{3}{4}\right)^{6}

p\left( X\geqslant1 \right)=1+\left( \dfrac{3}{4}\right)^{6}

p\left( X\geqslant1 \right)=-1-\left( \dfrac{3}{4}\right)^{6}

p\left( X\geqslant1 \right)=-1+\left( \dfrac{3}{4}\right)^{6}